Jak przełączyć się na inny Storyboard dla iPhone 5?

Question

Jak przełączyć się na inny Storyboard dla iPhone 5?

Podobnie jak aplikacja wykorzystuje różne storyboardy dla iPada i iPhone 'a, chciałbym, aby moja aplikacja używała innego storyboardu dla iPhone' a 5. Ponieważ nie ma opcji w Info.plist aby wybrać domyślny storyboard dla iPhone 5, jak programowo nazwać storyboard?

Nie chcę używać AutoLayout dla tej aplikacji, chyba że jest to absolutnie ostateczność. Rozumiem, jak wykryć, czy użytkownik korzysta z iPhone ' a 5 lub innego urządzenia o tym samym rozmiarze ekranu. Po prostu muszę dowiedz się, jak ustawić domyślny storyboard bez plisty.

27

ios xcode ios6 uistoryboard iphone-5

Author: user1486548, 2012-10-02

Source

2 answers

To działało dla mnie-lekkie udoskonalenie z owijaniem uzyskanie storyboardu w funkcji

-(UIStoryboard*) getStoryboard {   
    UIStoryboard *storyBoard = nil;
    if ([UIDevice currentDevice].userInterfaceIdiom == UIUserInterfaceIdiomPad) {         
        storyBoard = [UIStoryboard storyboardWithName:@"MainStoryboard_iPad" bundle:nil];
    }else{
        if ([UIDevice currentDevice].userInterfaceIdiom == UIUserInterfaceIdiomPhone){
            // The iOS device = iPhone or iPod Touch
            CGSize iOSDeviceScreenSize = [[UIScreen mainScreen] bounds].size;
            if (iOSDeviceScreenSize.height == 480){
                // iPhone 3/4x
                storyBoard = [UIStoryboard storyboardWithName:@"MainStoryboard_iPhone_4" bundle:nil];

            }else if (iOSDeviceScreenSize.height == 568){
                // iPhone 5 etc
                storyBoard = [UIStoryboard storyboardWithName:@"MainStoryboard_iPhone_5" bundle:nil];
            }
        }
    }

    ASSERT(storyBoard);
    return storyBoard;
}

UIStoryboard* mainStoryBoard = [self getStoryboard];
    self.initialViewController = [mainStoryBoard instantiateInitialViewController];
    self.window = [[UIWindow alloc] initWithFrame:[[UIScreen mainScreen] bounds]];
    self.window.rootViewController = self.initialViewController;
    [self.window makeKeyAndVisible];

4

Author: gheese,
Warning: date(): Invalid date.timezone value 'Europe/Kyiv', we selected the timezone 'UTC' for now. in /var/www/agent_stack/data/www/doraprojects.net/template/agent.layouts/content.php on line 54
2013-01-24 14:24:12

score 56 · Accepted Answer

Szukałem tej samej odpowiedzi kilka tygodni temu oto moje rozwiązanie nadzieja pomaga..

-(void)initializeStoryBoardBasedOnScreenSize {

    if ([UIDevice currentDevice].userInterfaceIdiom == UIUserInterfaceIdiomPhone)
{    // The iOS device = iPhone or iPod Touch


    CGSize iOSDeviceScreenSize = [[UIScreen mainScreen] bounds].size;

    if (iOSDeviceScreenSize.height == 480)
    {   // iPhone 3GS, 4, and 4S and iPod Touch 3rd and 4th generation: 3.5 inch screen (diagonally measured)

        // Instantiate a new storyboard object using the storyboard file named Storyboard_iPhone35
        UIStoryboard *iPhone35Storyboard = [UIStoryboard storyboardWithName:@"Storyboard_iPhone35" bundle:nil];

        // Instantiate the initial view controller object from the storyboard
        UIViewController *initialViewController = [iPhone35Storyboard instantiateInitialViewController];

        // Instantiate a UIWindow object and initialize it with the screen size of the iOS device
        self.window = [[UIWindow alloc] initWithFrame:[[UIScreen mainScreen] bounds]];

        // Set the initial view controller to be the root view controller of the window object
        self.window.rootViewController  = initialViewController;

        // Set the window object to be the key window and show it
        [self.window makeKeyAndVisible];
    }

    if (iOSDeviceScreenSize.height == 568)
    {   // iPhone 5 and iPod Touch 5th generation: 4 inch screen (diagonally measured)

        // Instantiate a new storyboard object using the storyboard file named Storyboard_iPhone4
        UIStoryboard *iPhone4Storyboard = [UIStoryboard storyboardWithName:@"Storyboard_iPhone4" bundle:nil];

        // Instantiate the initial view controller object from the storyboard
        UIViewController *initialViewController = [iPhone4Storyboard instantiateInitialViewController];

        // Instantiate a UIWindow object and initialize it with the screen size of the iOS device
        self.window = [[UIWindow alloc] initWithFrame:[[UIScreen mainScreen] bounds]];

        // Set the initial view controller to be the root view controller of the window object
        self.window.rootViewController  = initialViewController;

        // Set the window object to be the key window and show it
        [self.window makeKeyAndVisible];
    }

    } else if ([UIDevice currentDevice].userInterfaceIdiom == UIUserInterfaceIdiomPad)

    {   // The iOS device = iPad

    UISplitViewController *splitViewController = (UISplitViewController *)self.window.rootViewController;
    UINavigationController *navigationController = [splitViewController.viewControllers lastObject];
    splitViewController.delegate = (id)navigationController.topViewController;

    }
}

Wywołanie tej metody Pod AppDelegate ddiFinishLaunchingWithOptions: metoda A także nie zapomnij nazwy swoich storyboardów poprawnie

Nadzieja pomaga...