Get table and Index storage size in SQL server [closed]
Chcę uzyskać dane tabeli i przestrzeń indeksu dla każdej tabeli w mojej bazie danych:
Table Name Data Space Index Space
-------------------------------------------------------
Jak mogę osiągnąć ten wynik?
67
Author: Brian Tompsett - 汤莱恩, 2013-04-09
2 answers
To zapytanie wyświetli całkowitą wielkość, jaką zajmuje tabela-clustered index, heap i wszystkie niezakłócone indeksy:
SELECT
s.Name AS SchemaName,
t.NAME AS TableName,
p.rows AS RowCounts,
SUM(a.total_pages) * 8 AS TotalSpaceKB,
SUM(a.used_pages) * 8 AS UsedSpaceKB,
(SUM(a.total_pages) - SUM(a.used_pages)) * 8 AS UnusedSpaceKB
FROM
sys.tables t
INNER JOIN
sys.schemas s ON s.schema_id = t.schema_id
INNER JOIN
sys.indexes i ON t.OBJECT_ID = i.object_id
INNER JOIN
sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = p.index_id
INNER JOIN
sys.allocation_units a ON p.partition_id = a.container_id
WHERE
t.NAME NOT LIKE 'dt%' -- filter out system tables for diagramming
AND t.is_ms_shipped = 0
AND i.OBJECT_ID > 255
GROUP BY
t.Name, s.Name, p.Rows
ORDER BY
s.Name, t.Name
Jeśli chcesz oddzielić przestrzeń tabel od przestrzeni indeksu, musisz użyć AND i.index_id IN (0,1)
dla przestrzeni tabel (index_id = 0
jest przestrzenią sterty, index_id = 1
jest rozmiarem grupowanych stron index = data) i AND i.index_id > 1
dla przestrzeni tylko indeksu
153
Author: marc_s,
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2014-09-22 04:13:51
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2014-09-22 04:13:51
with pages as (
SELECT object_id, SUM (reserved_page_count) as reserved_pages, SUM (used_page_count) as used_pages,
SUM (case
when (index_id < 2) then (in_row_data_page_count + lob_used_page_count + row_overflow_used_page_count)
else lob_used_page_count + row_overflow_used_page_count
end) as pages
FROM sys.dm_db_partition_stats
group by object_id
), extra as (
SELECT p.object_id, sum(reserved_page_count) as reserved_pages, sum(used_page_count) as used_pages
FROM sys.dm_db_partition_stats p, sys.internal_tables it
WHERE it.internal_type IN (202,204,211,212,213,214,215,216) AND p.object_id = it.object_id
group by p.object_id
)
SELECT object_schema_name(p.object_id) + '.' + object_name(p.object_id) as TableName, (p.reserved_pages + isnull(e.reserved_pages, 0)) * 8 as reserved_kb,
pages * 8 as data_kb,
(CASE WHEN p.used_pages + isnull(e.used_pages, 0) > pages THEN (p.used_pages + isnull(e.used_pages, 0) - pages) ELSE 0 END) * 8 as index_kb,
(CASE WHEN p.reserved_pages + isnull(e.reserved_pages, 0) > p.used_pages + isnull(e.used_pages, 0) THEN (p.reserved_pages + isnull(e.reserved_pages, 0) - p.used_pages + isnull(e.used_pages, 0)) else 0 end) * 8 as unused_kb
from pages p
left outer join extra e on p.object_id = e.object_id
Uwzględnia tabele wewnętrzne, takie jak te używane do przechowywania XML.
Edit: jeśli podzielisz wartości data_kb
i index_kb
przez 1024.0, otrzymasz liczby, które widzisz w GUI.
14
Author: muhmud,
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2013-04-09 08:36:00
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2013-04-09 08:36:00