Zapytanie SQL server, aby uzyskać listę kolumn w tabeli wraz z typami danych, a nie NULL i ograniczeniami klucza podstawowego
Muszę napisać zapytanie na SQL server, aby uzyskać listę kolumn w konkretnej tabeli, jej powiązanych typów danych i ich długości, a jeśli nie są null. Udało mi się to zrobić. Ale teraz muszę również dostać się do tej samej tabeli przed kolumną-TRUE, jeśli jest to klucz podstawowy. Jak to zrobić ?
Tak powinno być wyjście:
Columns_name----Data type----Length----isnull----Pk
14 answers
Aby uniknąć powielania wierszy dla niektórych kolumn, użyj user_type_id zamiast system_type_id.
SELECT
c.name 'Column Name',
t.Name 'Data type',
c.max_length 'Max Length',
c.precision ,
c.scale ,
c.is_nullable,
ISNULL(i.is_primary_key, 0) 'Primary Key'
FROM
sys.columns c
INNER JOIN
sys.types t ON c.user_type_id = t.user_type_id
LEFT OUTER JOIN
sys.index_columns ic ON ic.object_id = c.object_id AND ic.column_id = c.column_id
LEFT OUTER JOIN
sys.indexes i ON ic.object_id = i.object_id AND ic.index_id = i.index_id
WHERE
c.object_id = OBJECT_ID('YourTableName')
Po prostu zastąp YourTableName
swoją rzeczywistą nazwą tabeli-działa dla SQL Server 2005 i nowszych.
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2014-03-31 13:41:44
Procedura składowana sp_columns zwraca szczegółowe informacje o tabeli.
exec sp_columns MyTable
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2010-03-10 17:50:02
Możesz użyć zapytania:
select COLUMN_NAME, DATA_TYPE, CHARACTER_MAXIMUM_LENGTH,
NUMERIC_PRECISION, DATETIME_PRECISION,
IS_NULLABLE
from INFORMATION_SCHEMA.COLUMNS
where TABLE_NAME='TableName'
Aby uzyskać wszystkie potrzebne metadane z wyjątkiem informacji Pk.
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2015-10-15 18:40:31
Spróbuj tego:
select COLUMN_NAME, DATA_TYPE, CHARACTER_MAXIMUM_LENGTH, IS_NULLABLE
from INFORMATION_SCHEMA.COLUMNS IC
where TABLE_NAME = 'tablename' and COLUMN_NAME = 'columnname'
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2012-11-22 10:11:34
W SQL 2012 możesz użyć:
EXEC sp_describe_first_result_set N'SELECT * FROM [TableName]'
To da ci nazwy kolumn wraz z ich właściwościami.
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2016-11-30 10:26:37
Aby mieć pewność, że uzyskasz odpowiednią długość, musisz rozważyć typy unicode jako szczególny przypadek. Zobacz kod poniżej.
Więcej informacji można znaleźć na stronie: https://msdn.microsoft.com/en-us/library/ms176106.aspx
SELECT
c.name 'Column Name',
t.name,
t.name +
CASE WHEN t.name IN ('char', 'varchar','nchar','nvarchar') THEN '('+
CASE WHEN c.max_length=-1 THEN 'MAX'
ELSE CONVERT(VARCHAR(4),
CASE WHEN t.name IN ('nchar','nvarchar')
THEN c.max_length/2 ELSE c.max_length END )
END +')'
WHEN t.name IN ('decimal','numeric')
THEN '('+ CONVERT(VARCHAR(4),c.precision)+','
+ CONVERT(VARCHAR(4),c.Scale)+')'
ELSE '' END
as "DDL name",
c.max_length 'Max Length in Bytes',
c.precision ,
c.scale ,
c.is_nullable,
ISNULL(i.is_primary_key, 0) 'Primary Key'
FROM
sys.columns c
INNER JOIN
sys.types t ON c.user_type_id = t.user_type_id
LEFT OUTER JOIN
sys.index_columns ic ON ic.object_id = c.object_id AND ic.column_id = c.column_id
LEFT OUTER JOIN
sys.indexes i ON ic.object_id = i.object_id AND ic.index_id = i.index_id
WHERE
c.object_id = OBJECT_ID('YourTableName')
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2015-03-10 19:57:36
Rozszerzając odpowiedź Alexa, możesz to zrobić, aby uzyskać ograniczenie PK
Select C.COLUMN_NAME, C.DATA_TYPE, C.CHARACTER_MAXIMUM_LENGTH, C.NUMERIC_PRECISION, C.IS_NULLABLE, TC.CONSTRAINT_NAME
From INFORMATION_SCHEMA.COLUMNS As C
Left Join INFORMATION_SCHEMA.TABLE_CONSTRAINTS As TC
On TC.TABLE_SCHEMA = C.TABLE_SCHEMA
And TC.TABLE_NAME = C.TABLE_NAME
And TC.CONSTRAINT_TYPE = 'PRIMARY KEY'
Where C.TABLE_NAME = 'Table'
Musiałem przeoczyć, że chcesz, aby flaga określała, czy dana kolumna była częścią PK zamiast nazwy ograniczenia PK. Do tego można by użyć:
Select C.COLUMN_NAME, C.DATA_TYPE, C.CHARACTER_MAXIMUM_LENGTH
, C.NUMERIC_PRECISION, C.NUMERIC_SCALE
, C.IS_NULLABLE
, Case When Z.CONSTRAINT_NAME Is Null Then 0 Else 1 End As IsPartOfPrimaryKey
From INFORMATION_SCHEMA.COLUMNS As C
Outer Apply (
Select CCU.CONSTRAINT_NAME
From INFORMATION_SCHEMA.TABLE_CONSTRAINTS As TC
Join INFORMATION_SCHEMA.CONSTRAINT_COLUMN_USAGE As CCU
On CCU.CONSTRAINT_NAME = TC.CONSTRAINT_NAME
Where TC.TABLE_SCHEMA = C.TABLE_SCHEMA
And TC.TABLE_NAME = C.TABLE_NAME
And TC.CONSTRAINT_TYPE = 'PRIMARY KEY'
And CCU.COLUMN_NAME = C.COLUMN_NAME
) As Z
Where C.TABLE_NAME = 'Table'
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2010-03-11 01:53:17
IF EXISTS (SELECT 1 FROM INFORMATION_SCHEMA.TABLES
WHERE TABLE_TYPE = 'BASE TABLE' AND TABLE_NAME = 'Table')
BEGIN
SELECT COLS.COLUMN_NAME, COLS.DATA_TYPE, COLS.CHARACTER_MAXIMUM_LENGTH,
(SELECT 'Yes' FROM INFORMATION_SCHEMA.TABLE_CONSTRAINTS TC JOIN INFORMATION_SCHEMA.KEY_COLUMN_USAGE KCU
ON COLS.TABLE_NAME = TC.TABLE_NAME
AND TC.CONSTRAINT_TYPE = 'PRIMARY KEY'
AND KCU.TABLE_NAME = TC.TABLE_NAME
AND KCU.CONSTRAINT_NAME = TC.CONSTRAINT_NAME
AND KCU.COLUMN_NAME = COLS.COLUMN_NAME) AS KeyX
FROM INFORMATION_SCHEMA.COLUMNS COLS WHERE TABLE_NAME = 'Table' ORDER BY KeyX DESC, COLUMN_NAME
END
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2013-05-22 09:53:09
Rzucając kolejną odpowiedź na ring, to da ci te kolumny i więcej:
SELECT col.TABLE_CATALOG AS [Database]
, col.TABLE_SCHEMA AS Owner
, col.TABLE_NAME AS TableName
, col.COLUMN_NAME AS ColumnName
, col.ORDINAL_POSITION AS OrdinalPosition
, col.COLUMN_DEFAULT AS DefaultSetting
, col.DATA_TYPE AS DataType
, col.CHARACTER_MAXIMUM_LENGTH AS MaxLength
, col.DATETIME_PRECISION AS DatePrecision
, CAST(CASE col.IS_NULLABLE
WHEN 'NO' THEN 0
ELSE 1
END AS bit)AS IsNullable
, COLUMNPROPERTY(OBJECT_ID('[' + col.TABLE_SCHEMA + '].[' + col.TABLE_NAME + ']'), col.COLUMN_NAME, 'IsIdentity')AS IsIdentity
, COLUMNPROPERTY(OBJECT_ID('[' + col.TABLE_SCHEMA + '].[' + col.TABLE_NAME + ']'), col.COLUMN_NAME, 'IsComputed')AS IsComputed
, CAST(ISNULL(pk.is_primary_key, 0)AS bit)AS IsPrimaryKey
FROM INFORMATION_SCHEMA.COLUMNS AS col
LEFT JOIN(SELECT SCHEMA_NAME(o.schema_id)AS TABLE_SCHEMA
, o.name AS TABLE_NAME
, c.name AS COLUMN_NAME
, i.is_primary_key
FROM sys.indexes AS i JOIN sys.index_columns AS ic ON i.object_id = ic.object_id
AND i.index_id = ic.index_id
JOIN sys.objects AS o ON i.object_id = o.object_id
LEFT JOIN sys.columns AS c ON ic.object_id = c.object_id
AND c.column_id = ic.column_id
WHERE i.is_primary_key = 1)AS pk ON col.TABLE_NAME = pk.TABLE_NAME
AND col.TABLE_SCHEMA = pk.TABLE_SCHEMA
AND col.COLUMN_NAME = pk.COLUMN_NAME
WHERE col.TABLE_NAME = 'YourTableName'
AND col.TABLE_SCHEMA = 'dbo'
ORDER BY col.TABLE_NAME, col.ORDINAL_POSITION;
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2014-03-12 17:29:51
select
c.name as [column name],
t.name as [type name],
tbl.name as [table name]
from sys.columns c
inner join sys.types t
on c.system_type_id = t.system_type_id
inner join sys.tables tbl
on c.object_id = tbl.object_id
where
c.object_id = OBJECT_ID('YourTableName1')
and
t.name like '%YourSearchDataType%'
union
(select
c.name as [column name],
t.name as [type name],
tbl.name as [table name]
from sys.columns c
inner join sys.types t
on c.system_type_id = t.system_type_id
inner join sys.tables tbl
on c.object_id = tbl.object_id
where
c.object_id = OBJECT_ID('YourTableName2')
and
t.name like '%YourSearchDataType%')
union
(select
c.name as [column name],
t.name as [type name],
tbl.name as [table name]
from sys.columns c
inner join sys.types t
on c.system_type_id = t.system_type_id
inner join sys.tables tbl
on c.object_id = tbl.object_id
where
c.object_id = OBJECT_ID('YourTableName3')
and
t.name like '%YourSearchDataType%')
order by tbl.name
aby wyszukać kolumnę, w której tabeli, na podstawie typu danych wyszukiwania dla trzech różnych tabeli w jednej bazie danych. To zapytanie można rozszerzyć do " n " tabel.
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2014-01-14 09:15:52
Wybierz nazwę tabeli w Edytorze zapytań wybierz nazwę i naciśnij Alt + F1, a spowoduje to wyświetlenie wszystkich informacji o tabeli.
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2015-01-22 05:55:54
SELECT COLUMN_NAME, IS_NULLABLE, DATA_TYPE, CHARACTER_MAXIMUM_LENGTH FROM information_schema.columns WHERE table_name = '<name_of_table_or_view>'
Uruchom SELECT *
w powyższej instrukcji, aby zobaczyć, co information_schema.zwraca kolumny.
Na to pytanie udzielono wcześniej odpowiedzi - https://stackoverflow.com/a/11268456/6169225
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2017-10-19 13:38:44
SELECT
T.NAME AS [TABLE NAME]
,C.NAME AS [COLUMN NAME]
,P.NAME AS [DATA TYPE]
,P.MAX_LENGTH AS [Max_SIZE]
,C.[max_length] AS [ActualSizeUsed]
,CAST(P.PRECISION AS VARCHAR) +'/'+ CAST(P.SCALE AS VARCHAR) AS [PRECISION/SCALE]
FROM SYS.OBJECTS AS T
JOIN SYS.COLUMNS AS C
ON T.OBJECT_ID = C.OBJECT_ID
JOIN SYS.TYPES AS P
ON C.SYSTEM_TYPE_ID = P.SYSTEM_TYPE_ID
AND C.[user_type_id] = P.[user_type_id]
WHERE T.TYPE_DESC='USER_TABLE'
AND T.name = 'InventoryStatus'
ORDER BY 2
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2016-04-28 08:33:21
Find combine result for Datatype and Length and is nullable in form of" NULL "and" Not null " Use below query.
SELECT c.name AS 'Column Name',
t.name + '(' + cast(c.max_length as varchar(50)) + ')' As 'DataType',
case
WHEN c.is_nullable = 0 then 'null' else 'not null'
END AS 'Constraint'
FROM sys.columns c
JOIN sys.types t
ON c.user_type_id = t.user_type_id
WHERE c.object_id = Object_id('TableName')
Znajdziesz wynik, jak pokazano poniżej.
Dziękuję.Warning: date(): Invalid date.timezone value 'Europe/Kyiv', we selected the timezone 'UTC' for now. in /var/www/agent_stack/data/www/doraprojects.net/template/agent.layouts/content.php on line 54
2018-05-14 10:04:53