Lista Pythona Sortuj malejąco

Question

Lista Pythona Sortuj malejąco

Jak mogę posortować tę listę w porządku malejącym?

timestamp = [
    "2010-04-20 10:07:30",
    "2010-04-20 10:07:38",
    "2010-04-20 10:07:52",
    "2010-04-20 10:08:22",
    "2010-04-20 10:08:22",
    "2010-04-20 10:09:46",
    "2010-04-20 10:10:37",
    "2010-04-20 10:10:58",
    "2010-04-20 10:11:50",
    "2010-04-20 10:12:13",
    "2010-04-20 10:12:13",
    "2010-04-20 10:25:38"
]

267

python sorting reverse

Author: Mark Amery, 2010-11-15

Source

5 answers

To da ci posortowaną wersję tablicy.

sorted(timestamp, reverse=True)

Jeśli chcesz sortować w miejscu:

timestamp.sort(reverse=True)

314

Author: Marcelo Cantos,
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2010-11-15 10:47:15

Możesz po prostu to zrobić:

timestamp.sort(reverse=True)

41

Author: Wolph,
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2016-11-13 14:59:21

Ponieważ twoja lista jest już w porządku rosnącym, możemy po prostu odwrócić listę.

>>> timestamp.reverse()
>>> timestamp
['2010-04-20 10:25:38', 
'2010-04-20 10:12:13', 
'2010-04-20 10:12:13', 
'2010-04-20 10:11:50', 
'2010-04-20 10:10:58', 
'2010-04-20 10:10:37', 
'2010-04-20 10:09:46', 
'2010-04-20 10:08:22',
'2010-04-20 10:08:22', 
'2010-04-20 10:07:52', 
'2010-04-20 10:07:38', 
'2010-04-20 10:07:30']

7

Author: Russell Dias,
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2010-11-15 10:42:18

Ty prosty typ:

timestamp.sort()
timestamp=timestamp[::-1]

3

Author: mostafa elmadany,
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2017-10-06 17:13:58

score 307 · Accepted Answer

W jednym wierszu, używając lambda:

timestamp.sort(key=lambda x: time.strptime(x, '%Y-%m-%d %H:%M:%S')[0:6], reverse=True)

Przekazanie funkcji list.sort:

def foo(x):
    return time.strptime(x, '%Y-%m-%d %H:%M:%S')[0:6]

timestamp.sort(key=foo, reverse=True)

307

Author: Ignacio Vazquez-Abrams,
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2018-01-11 06:16:12