Jak wrzucić JSON na serwer używając C#?
Oto kod, którego używam:
// create a request
HttpWebRequest request = (HttpWebRequest)
WebRequest.Create(url); request.KeepAlive = false;
request.ProtocolVersion = HttpVersion.Version10;
request.Method = "POST";
// turn our request string into a byte stream
byte[] postBytes = Encoding.UTF8.GetBytes(json);
// this is important - make sure you specify type this way
request.ContentType = "application/json; charset=UTF-8";
request.Accept = "application/json";
request.ContentLength = postBytes.Length;
request.CookieContainer = Cookies;
request.UserAgent = currentUserAgent;
Stream requestStream = request.GetRequestStream();
// now send it
requestStream.Write(postBytes, 0, postBytes.Length);
requestStream.Close();
// grab te response and print it out to the console along with the status code
HttpWebResponse response = (HttpWebResponse)request.GetResponse();
string result;
using (StreamReader rdr = new StreamReader(response.GetResponseStream()))
{
result = rdr.ReadToEnd();
}
return result;
Kiedy to uruchamiam, zawsze dostaję wewnętrzny błąd serwera 500.
Co robię źle?11 answers
Sposób w jaki to robię i działa to:
var httpWebRequest = (HttpWebRequest)WebRequest.Create("http://url");
httpWebRequest.ContentType = "application/json";
httpWebRequest.Method = "POST";
using (var streamWriter = new StreamWriter(httpWebRequest.GetRequestStream()))
{
string json = "{\"user\":\"test\"," +
"\"password\":\"bla\"}";
streamWriter.Write(json);
streamWriter.Flush();
streamWriter.Close();
}
var httpResponse = (HttpWebResponse)httpWebRequest.GetResponse();
using (var streamReader = new StreamReader(httpResponse.GetResponseStream()))
{
var result = streamReader.ReadToEnd();
}
Napisałem bibliotekę, aby wykonać to zadanie w prostszy sposób, jest tutaj: https://github.com/ademargomes/JsonRequest
Mam nadzieję, że to pomoże.Warning: date(): Invalid date.timezone value 'Europe/Kyiv', we selected the timezone 'UTC' for now. in /var/www/agent_stack/data/www/doraprojects.net/template/agent.layouts/content.php on line 54
2016-03-20 13:43:25
Rozwiązanie Ademara może być ulepszone poprzez wykorzystanie metody JavaScriptSerializer
Serialize
w celu zapewnienia niejawnej konwersji obiektu na JSON.
Dodatkowo możliwe jest wykorzystanie domyślnej funkcjonalności instrukcji using
w celu pominięcia jawnego wywołania Flush
i Close
.
var httpWebRequest = (HttpWebRequest)WebRequest.Create("http://url");
httpWebRequest.ContentType = "application/json";
httpWebRequest.Method = "POST";
using (var streamWriter = new StreamWriter(httpWebRequest.GetRequestStream()))
{
string json = new JavaScriptSerializer().Serialize(new
{
user = "Foo",
password = "Baz"
});
streamWriter.Write(json);
}
var httpResponse = (HttpWebResponse)httpWebRequest.GetResponse();
using (var streamReader = new StreamReader(httpResponse.GetResponseStream()))
{
var result = streamReader.ReadToEnd();
}
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2015-06-02 02:54:01
Poza postem Seana, nie jest konieczne zagnieżdżanie poleceń using. Przez using
StreamWriter zostanie spłukany i zamknięty na końcu bloku, więc nie ma potrzeby jawnego wywoływania metod Flush()
i Close()
:
var request = (HttpWebRequest)WebRequest.Create("http://url");
request.ContentType = "application/json";
request.Method = "POST";
using (var streamWriter = new StreamWriter(request.GetRequestStream()))
{
string json = new JavaScriptSerializer().Serialize(new
{
user = "Foo",
password = "Baz"
});
streamWriter.Write(json);
}
var response = (HttpWebResponse)request.GetResponse();
using (var streamReader = new StreamReader(response.GetResponseStream()))
{
var result = streamReader.ReadToEnd();
}
Warning: date(): Invalid date.timezone value 'Europe/Kyiv', we selected the timezone 'UTC' for now. in /var/www/agent_stack/data/www/doraprojects.net/template/agent.layouts/content.php on line 54
2016-03-20 13:43:53
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2017-05-23 11:54:48
Jeśli chcesz wywołać jest asynchronicznie, użyj
var request = HttpWebRequest.Create("http://www.maplegraphservices.com/tokkri/webservices/updateProfile.php?oldEmailID=" + App.currentUser.email) as HttpWebRequest;
request.Method = "POST";
request.ContentType = "text/json";
request.BeginGetRequestStream(new AsyncCallback(GetRequestStreamCallback), request);
private void GetRequestStreamCallback(IAsyncResult asynchronousResult)
{
HttpWebRequest request = (HttpWebRequest)asynchronousResult.AsyncState;
// End the stream request operation
Stream postStream = request.EndGetRequestStream(asynchronousResult);
// Create the post data
string postData = JsonConvert.SerializeObject(edit).ToString();
byte[] byteArray = Encoding.UTF8.GetBytes(postData);
postStream.Write(byteArray, 0, byteArray.Length);
postStream.Close();
//Start the web request
request.BeginGetResponse(new AsyncCallback(GetResponceStreamCallback), request);
}
void GetResponceStreamCallback(IAsyncResult callbackResult)
{
HttpWebRequest request = (HttpWebRequest)callbackResult.AsyncState;
HttpWebResponse response = (HttpWebResponse)request.EndGetResponse(callbackResult);
using (StreamReader httpWebStreamReader = new StreamReader(response.GetResponseStream()))
{
string result = httpWebStreamReader.ReadToEnd();
stat.Text = result;
}
}
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2014-01-29 21:54:30
The HttpClient
type jest nowszą implementacją WebClient
i HttpWebRequest
.
Możesz po prostu użyć następujących linii.
string myJson = "{'Username': 'myusername','Password':'pass'}";
using (var client = new HttpClient())
{
var response = await client.PostAsync(
"http://yourUrl",
new StringContent(myJson, Encoding.UTF8, "application/json"));
}
Gdy potrzebujesz HttpClient więcej niż raz, zaleca się utworzenie tylko jednej instancji i ponowne jej użycie lub użycie nowej HttpClientFactory.
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2018-08-07 12:54:08
Ostatnio wymyśliłem o wiele prostszy sposób, aby opublikować JSON, z dodatkowym krokiem konwersji z modelu w mojej aplikacji. Zauważ, że musisz utworzyć model [JsonObject] dla kontrolera, aby uzyskać wartości i wykonać konwersję.
Zapytanie:
var model = new MyModel();
using (var client = new HttpClient())
{
var uri = new Uri("XXXXXXXXX");
var json = new JavaScriptSerializer().Serialize(model);
var stringContent = new StringContent(json, Encoding.UTF8, "application/json");
var response = await Client.PutAsync(uri,stringContent).Result;
...
...
}
Model:
[JsonObject]
[Serializable]
public class MyModel
{
public Decimal Value { get; set; }
public string Project { get; set; }
public string FilePath { get; set; }
public string FileName { get; set; }
}
Strona serwera:
[HttpPut]
public async Task<HttpResponseMessage> PutApi([FromBody]MyModel model)
{
...
...
}
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2017-01-20 06:46:13
Ta opcja nie jest wymieniona:
using (var client = new HttpClient())
{
client.BaseAddress = new Uri("http://localhost:9000/");
client.DefaultRequestHeaders.Accept.Add(new MediaTypeWithQualityHeaderValue("application/json"));
var foo = new User
{
user = "Foo",
password = "Baz"
}
await client.PostAsJsonAsync("users/add", foo);
}
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2016-09-26 12:04:15
Innym i czystym sposobem na osiągnięcie tego jest użycie HttpClient w następujący sposób:
public async Task<HttpResponseMessage> PostResult(string url, ResultObject resultObject)
{
using (var client = new HttpClient())
{
HttpResponseMessage response = new HttpResponseMessage();
try
{
response = await client.PostAsJsonAsync(url, resultObject);
}
catch (Exception ex)
{
throw ex
}
return response;
}
}
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2017-06-01 07:09:13
var data = Encoding.ASCII.GetBytes(json);
byte[] postBytes = Encoding.UTF8.GetBytes(json);
Użyj ASCII zamiast UFT8
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2017-03-15 17:51:57
W końcu wywołałem w trybie synchronizacji, włączając .Result
HttpResponseMessage response = null;
try
{
using (var client = new HttpClient())
{
response = client.PostAsync(
"http://localhost:8000/....",
new StringContent(myJson,Encoding.UTF8,"application/json")).Result;
if (response.IsSuccessStatusCode)
{
MessageBox.Show("OK");
}
else
{
MessageBox.Show("NOK");
}
}
}
catch (Exception ex)
{
MessageBox.Show("ERROR");
}
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2018-02-27 10:34:45